remember pressed keys and release the same keys when the physical switch is opened, even if the layer has changed between key down and key up and a different key is now active for that matrix position

This commit is contained in:
Christian Tu 2021-09-17 15:59:57 +02:00
parent 27cf8e7d4d
commit f36a18513b
2 changed files with 13 additions and 8 deletions

View File

@ -8,9 +8,6 @@ def passthrough(key, keyboard, *args, **kwargs):
def default_pressed(key, keyboard, KC, coord_int=None, coord_raw=None, *args, **kwargs): def default_pressed(key, keyboard, KC, coord_int=None, coord_raw=None, *args, **kwargs):
keyboard.hid_pending = True keyboard.hid_pending = True
if coord_int is not None:
keyboard._coordkeys_pressed[coord_int] = key
keyboard.keys_pressed.add(key) keyboard.keys_pressed.add(key)
return keyboard return keyboard
@ -22,10 +19,6 @@ def default_released(
keyboard.hid_pending = True keyboard.hid_pending = True
keyboard.keys_pressed.discard(key) keyboard.keys_pressed.discard(key)
if coord_int is not None:
keyboard.keys_pressed.discard(keyboard._coordkeys_pressed.get(coord_int, None))
keyboard._coordkeys_pressed[coord_int] = None
return keyboard return keyboard

View File

@ -148,8 +148,20 @@ class KMKKeyboard:
print('MatrixChange(col={} row={} pressed={})'.format(col, row, is_pressed)) print('MatrixChange(col={} row={} pressed={})'.format(col, row, is_pressed))
int_coord = intify_coordinate(row, col) int_coord = intify_coordinate(row, col)
kc_changed = None
if not is_pressed:
kc_changed = self._coordkeys_pressed[int_coord]
if self.debug_enabled:
print('PressedKeyResolution(key={})'.format(self.state_layer_key))
if kc_changed is None:
kc_changed = self._find_key_in_map(int_coord, row, col) kc_changed = self._find_key_in_map(int_coord, row, col)
if is_pressed:
self._coordkeys_pressed[int_coord] = kc_changed
else:
self._coordkeys_pressed[int_coord] = None
if kc_changed is None: if kc_changed is None:
print('MatrixUndefinedCoordinate(col={} row={})'.format(col, row)) print('MatrixUndefinedCoordinate(col={} row={})'.format(col, row))
return self return self